Mini Project--- Employe Information - Input & Display

The following table containing information about employees of an organization, develop a small java application, which accepts employee id from the command prompt and displays
the following details as output:

Emp No Emp Name Department Designation and Salary

You may assume that the array is initialized with the following details:

Emp No.	Emp Name	Join Date	Desig Code	Dept	Basic	HRA	IT
1001	Ashish	01/04/2009	e	R&D	20000	8000	3000
1002	Sushma	23/08/2012	c	PM	30000	12000	9000
1003	Rahul	12/11/2008	k	Acct	10000	8000	1000
1004	Chahat	29/01/2013	r	Front Desk	12000	6000	2000
1005	Ranjan	16/07/2005	m	Engg	50000	20000	20000
1006	Suman	1/1/2000	e	Manu factur ing	23000	9000	4400
1007	Tanmay	12/06/2006	c	PM	29000	12000	10000

Salary is calculated as Basic+HRA+DA-IT. (DA details are given in the Designation table)
Designation details :

Designation Code	Designation	DA
e	Engineer	20000
c	Consultant	32000
k	Clerk	12000
r	Receptionist	15000

m

Manager

40000

Use Switch-Case to print Designation in the output and to find the value of DA for a particular
employee.
O/P Expected:
1. Assuming that your class name is Hello, and you execute your code asjava Hello 1003, it should display the following output :

Emp No. Emp Name Department Designation Salary
1003 Rahul Acct Clerk 29000

2. java Hello 123

There is no employee with empid : 123  

Solution:

public class Hello {

       public static String Designation;

       public static int DA;

public static void main(String args[]) {

       if(args.length==0)

              System.out.println("Please Provide Emp No.");

       else {

              int EmpNo =Integer.parseInt(args[0]);

              String EmpName,Department;

              int Basic,HRA,IT,Salary;

              char DesigCode;

              switch(EmpNo){

             

              case 1001:

                     EmpName="Ashish";

                     DesigCode='e';

                     Department="R&D";

                     Basic=20000;

                     HRA=8000;

                     IT=3000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                     System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t\t"+Designation+"\t"+Salary);

                     break;

              case 1002:

                  EmpName="Sushma";

                     DesigCode='c';

                     Department="PM";

                     Basic=30000;

                  HRA=12000;

                     IT=9000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                     System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t\t"+Designation+"\t"+Salary);

                     break;

              case 1003:

                     EmpName="Rahul";

                     DesigCode='k';

                     Department="Acct";

                     Basic=10000;

                     HRA=8000;

                     IT=1000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                   System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t\t"+Designation+"\t\t"+Salary);

                     break;

              case 1004:

                     EmpName="Chahat";

                     DesigCode='r';

                     Department="Front Desk";

                     Basic=12000;

                     HRA=6000;

                     IT=2000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                     System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t"+Designation+"\t"+Salary);

                     break;

              case 1005:

                     EmpName="Ranjan";

                     DesigCode='m';

                     Department="Engg";

                     Basic=50000;

                     HRA=20000;

                     IT=20000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                   System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t\t"+Designation+"\t\t"+Salary);

                     break;

              case 1006:

                     EmpName="Suman";

                     DesigCode='e';

                     Department="Manufacturing";

                     Basic=23000;

                     HRA=9000;

                     IT=4400;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                     System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t"+Designation+"\t"+Salary);

                     break;

              case 1007:

                     EmpName="Tanmay";

                     DesigCode='c';

                     Department="PM";

                     Basic=29000;

                     HRA=12000;

                     IT=10000;

                     getDesignation(DesigCode);

                     Salary =Basic+HRA+DA-IT;

                     System.out.println("Emp No.\t\tEmp Name\tDepartment\tDesignation\tSalary");

                     System.out.println(EmpNo+"\t\t"+EmpName+"\t\t"+Department+"\t\t"+Designation+"\t"+Salary);

                     break;

              default:System.out.println("There is no employee with empid :"+EmpNo);

              }

             

       }

             

}

public static  void getDesignation(char DesignationCode){

       switch(DesignationCode){

       case 'e': {

              Designation="Engineer";

              DA=20000;

              break;

       }

       case 'c': {

              Designation="Consultant";

              DA=32000;

              break;

              }

       case 'k':  {

              Designation="Clerk";

              DA=12000;

              break;

              }

       case 'r':  {

                           Designation="Receptionist";

                           DA=15000;

                           break;

                     }

       case 'm':  {

              Designation="Manager";

              DA=40000;

              break;

              }

       }

       }

}

Write a program to accept the age of 20 students of a class. Re-arrange the data in ascending order (smallest value to largest value). Display the age of the youngest and eldest student in the class. Also display number of students in the class for each age present in the list.

import java.util.Scanner;

public class Hello {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the no of students ");
int n=sc.nextInt();
System.out.println("Enter the age of students ");
int arr[]=new int[n];
for(int i=0;i<n;i++) {
arr[i]=sc.nextInt();
}
for(int i=0;i<n;i++) {
for(int j=i+1;j<n;j++) {
if(arr[i]>arr[j]) {
int temp=arr[i];
                    arr[i]=arr[j];
                    arr[j]=temp;
}
}
}
System.out.println("Age in ascending order ");
for(int i=0;i<n;i++) {
System.out.print(arr[i]+" ");
}
System.out.println("");
System.out.println("age of the youngest student is "+arr[0]+" and age of the eldest student is "+arr[n-1]);

for(int i=0; i<n ;i++){
        int count =1;
        while((i < n-1 )&& (arr[i] == arr[i+1]))
        {
        count++;
        i=i+1;
        }
        System.out.println(" The number of students of " +arr[i]+" "+"is"+" " +count);
                         }
}
}